Prims Algorithm

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Approach: Greedy

See Minimum_Spanning_Tree

Implementation

for each u in V:
    key[u] = infinity   // cost array
    pi[u] = infinity    // from array
Q = new PriorityQueue(V)
key[root] = 0
while Q is not empty:
    u = extractMin(Q)
    # Reduce nodes
    for v in adj[u]:
        if v in Q and w[u,v] < key[v]:
            key[v] = w[u,v]

Analysis

Priority queue is slower than array when the graph is dense, so sometimes it's better to use Dijsktra's algorithm.

Proof: Greedy

Suboptimality

Given MST tree for the graph G

where the number of edges is , the weight of edges is minimum, and the tree is spanning.

Consider , where X is a leaf node.

Prove that is a MST for the subproblem

By contradiction, assume that is not optimal. There must be such that

Adding the edge (x, y) back to both graphs

is a viable tree.

Therefore, OPT is not the optimal solution.

By contradiction, must be optimal.