Shortest Path Problem: Difference between revisions
From Rice Wiki
No edit summary Tag: Manual revert |
No edit summary |
||
Line 54: | Line 54: | ||
can detect it by running an extra time, since if there is a negative | can detect it by running an extra time, since if there is a negative | ||
cycle, the run time will improve. | cycle, the run time will improve. | ||
[[Category:Algorithms]] |
Revision as of 03:43, 5 March 2024
Definitions
A path is a sequence of nodes such that for all consecutive nodes, there exist an edge
Let there be a weight assigned to each edge.
Single Source Shortest Path (SSSP)
Given a graph , source node , outupt the shortest path from the source
Variants
- Single destination problem: shortest path from all nodes to a single destination
- Single pair problem: Shortest path between input pair
Implementation: Bellman Ford
All shortest path must have edges. If this condition is not satisfied, there is a cycle in in the path, and therefore it is not the shortest.
OPT(a, n-1) = min(w(u,a) + OPT(n-1, u) for all (u, a) in E)
Time complexity:
- Sparse:
- Dense:
// G: Graph with vertices (V) and edges (E) // w[e]: weight of edge e // S: starting node Bellman-Ford(G, w, S) V, E = G pi[v] = null for all v // traceback // initialize all shortest path algo d[v] = infty for all v d[s] = 0 for i from 1 to |V| - 1: for all (u,v) in E if d[v] > d[u] + w(u, v): d[v] = d[u] + w(u,v) pi[v] = u; for all (u, v) in E: if d[v] > d[u] + w(u, v): // has negative cycle return false
This accounts for negative edges but not negative cycles. Bellman Ford can detect it by running an extra time, since if there is a negative cycle, the run time will improve.