Integrating factor: Difference between revisions
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<math>y(t) = \frac{1}{\mu(t)}\int \mu g dt + C </math> | <math>y(t) = \frac{1}{\mu(t)}\int \mu g dt + C </math> | ||
[[Category:Differential Equations]] | |||
Revision as of 19:28, 17 May 2024
Integrating factor is a method to solve scalar Linear First Order ODEs. It takes advantage of the product rule of derivatives
Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle (\mu y)' = \mu' y + \mu y'}
and attempts to move all y terms into the same differential order.
Note that Separation of variables is generally easier when both options are available.
Procedure
Consider a linear first order ODE.
Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle y' + p(t) y = g(t)}
We multiply bothsides by integrating factor Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \mu(t)} such that the left hand side to be the exact derivative of a product. For this to work, we need
Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \mu' = \mu p}
Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \mu(t) = C \exp\left[ \int p dt \right]}
Applying the integrating factor, we have
Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \begin{aligned} \mu(t) y + \mu(t) p(t) y &= \mu(t) g(t) \\ \mu y' + \mu ' y &= \mu g \\ (\mu y)' &= \mu g \end{aligned}}
From there, simple integration and algebra will solve the equation.
Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle y(t) = \frac{1}{\mu(t)}\int \mu g dt + C }
